1、习题1.40 2.2 11 0.2 20log1120.8 o v i v AV V v dB = =或 dB VV mAi R v i i A i L o i o i 8 .26log2220 22 1 100 2 . 2 = = 或 () dB WW iv R v P P A ii L o i o p 8 .23log24210 242 22 2 2 = = = 或 mVmAP dc 1202032= mWPPPP odcidis 8 .95=+= %2 .20%100= dc o P P (a)当VI=2V时， Vomax=L+ =10V 当VI=Vo+2时，Vomin=L- =1.31
2、7V 此时VI=3.317V （b）偏置点 Vo=5V,此时 VI=3V (c) 习题1.44 ()VVv v v A Vv I Vv i o v i i 10210 3 3 = = = = () ()tVtVV tVvd iii io 2cos5 . 2cos105 . 25 2cos3510)( 2 2 2 = += VVmVV V V oi i i 4 . 04001. 0 10 5 . 2 2 = 习题1.46 VVA vo 100= dBWW R v R v A dBVV v v v v A i i L o p i i i o v 17.791026.8 1 .399 .90 101
3、00 100 100 7 2 2 或 或 = = + = W R V P V V V V V VmAVmAi L opeak o ipeak RMS opeak ipeak opeako 5 . 0 2 078. 0 29 .90 10 9 .90 10100100,100 2 max = = =则若 习题1.51 Vvv VV RR R RR R RR R RR R v v v v v v v v v v VV mV V v v so oL L oi i oi i si i i o i i i i s i s o s o 066. 26 .206 6 .206 101010 200 10 2 323 3 12 2 1 1 32 3 1 21 = = + + + + = = = 实际： 理论：
